Operation Sports Forums - View Single Post - OSFC- Bud Shootout(2012)

BurghFan · 02-13-2012, 12:55 PM

I just had a thought for a way we can get everyone in this race (and perhaps for the All-Star where their are fewer drivers than OSFC participants).

What if instead of picking 1 driver, everyone picks 2 drivers so that every participant has a unique pair of drivers. In this way, more than 1 person can have a driver in common, but no 2 people can have both drivers in common. The winner would then be whoever picked the pair with the highest combined finish. Ties could then be broken by giving it to the person who's driver had the highest finish. for instance.

Person A's drivers finish 2nd and 5th
Person B's drivers finish 3rd and 4th

Then Person A wins by having the driver with the highest finish.

02-13-2012, 12:55 PM	#2
BurghFan #BurghProud OVR: 34 Join Date: Jul 2009 Location: Pittsburgh, PA Posts: 10,086 Blog Entries: 2	Re: OSFC- Bud Shootout(2012) I just had a thought for a way we can get everyone in this race (and perhaps for the All-Star where their are fewer drivers than OSFC participants). What if instead of picking 1 driver, everyone picks 2 drivers so that every participant has a unique pair of drivers. In this way, more than 1 person can have a driver in common, but no 2 people can have both drivers in common. The winner would then be whoever picked the pair with the highest combined finish. Ties could then be broken by giving it to the person who's driver had the highest finish. for instance. Person A's drivers finish 2nd and 5th Person B's drivers finish 3rd and 4th Then Person A wins by having the driver with the highest finish. __________________ Moderator Steelers: IX, X, XIII, XIV, XL, XLIII Penguins:1990/91, 1991/92, 2008/09, 20015/16, 2016/17 Pirates:1909, 1925, 1960, 1971, 1979 Panthers (FB): 1915, 1916, 1918, 1929, 1931, 1934, 1936, 1937, 1976 Panthers (MBB): 1927/28, 1929/30