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Airhog
03-22-2003, 07:48 PM
Here is a math problem, and I hope someone could provide an anwser.

How many different possible combinations are there when filling a bracket in?

In other words, how many different brackets could one make?

How many different brackets could one make if none of the 10-16 seeds made it past round 2

JeeberD
03-22-2003, 07:50 PM
a million jillion kabillion...

Airhog
03-22-2003, 07:51 PM
I dont think this is correct, but im guessing 384 different brackets

GoldenEagle
03-22-2003, 07:51 PM
Is this a puzzle?

JeeberD
03-22-2003, 07:55 PM
Somebody get Quik in here, he'll solve it for us...

henry296
03-22-2003, 07:58 PM
All combinations is

64 X 32 X 16 X 8 x 4 x 2 which gives me 2,097,152

Todd

Marmel
03-22-2003, 08:37 PM
ignore

Airhog
03-22-2003, 08:57 PM
Im thinking its 64^6th power which would be 68,719,476,736 but I dont know enough math to be sure my anwser is correct.


If thats true then not including the 10-16 seed would be something like (64^2)+(36^4)=1,683,712