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InchWord - a new FOFC word puzzle/contest
It's been a pretty long while since I posted an original puzzle/contest here -- thought it might be worth a try again. I will do my best to be clear with the setup and scoring.
The goal of this game is to find an English word that contains, in sequence but not necessarily adjacently, multiple letters of the alphabet. For a word entered under the letter "E" fir instance, it must contain an E, and then somewhere later in the word an F, and so forth. The more such letters you get into your word, and the more "efficiently" you do so, the higher your score will be for the word. SCORING: - Each consecutive letter of the alphabet that appears, in order, in your word is with an increasing point. For example, 4 such letters are worth 1+2+3+4 = 10 points. - Each letter in your word that is not part of the consecutive sequence is a 1 point penalty. - Each prefix, suffix, pluralization, or other change of your word away from its "root" is a cumulative deduction as well. The first add-on is a -1 penalty, the second is a -2, and so forth. - If you submit a word that someone other than a Scrabble champion or a computer dictionary has heard of and even used, you will gain the hard-earned respect and admiration of your peers. Which is nice. So... if we entered the word DEFYING, we would: -classify it under the letter D, the first scoring letter -award 10 points for the D,E,F, and G -subtract 3 points for the 3 letters not part of that sequence -subtract 1 extra point for using a suffix D: DEFyinG = 6 points In theory, we could allow up to 26 entries into the contest -- for words containing scoring sequences starting with each letter of the alphabet. We will use "Atari physics" for any series that reaches Z -- it will continue on to A if possible. So, give it some thought, and submit your entries in this thread. High scores for any given starting letter will be honored suitably. |
abdicate
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Courtesy of Mrs. A: absconded
a,b,c,d,e = 15 less 4 for superfluous letters and 1 for the suffix. Total of 10 points. |
My meager contributions:
Zap = 2 points. Code = 5 points. |
Misread the rules. :)
OPaQueRS root word: opaque modifier: -er modifier: -s o + p + q + r + s = 15 a, u, e = -3 2 modifiers = -3 Points: 9 |
hijack
8 points for me |
what happened to "I'm wit Stupid"
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Existentialism
-13 wait what? |
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I think the letters have to be in order in the word. |
defog = 8 pts
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luminous - 5 pts
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hijack
1+2+3+4 - 2 = 8 I'll try some more. Bah - Shorty beat me to this one. Never mind. |
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Unless I misread the rules, the letters have to appear in sequence. So abdicate only gets credit for a,b,c. You can't count the d because it comes before the c. |
ah, nuts. I'm a cheater, I guess. ;)
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Code = 6-1-0 = 5
Fighting = 10-4-1 = 6 Codefighting (?) for 28-5-2 = 21 Studioview (?) = 21-5-1 = 15 I do have my doubts these would qualify as correct english words, though. If they're not, I suppose Hijackmen (21-3-1=17) isn't a good english word either. |
ah yes, my all-time favorite instrument, the ghijak!
+14 |
Does the first letter of the word have to be the first letter of the series?
If not, do the letters at the beginning of the word count against you? |
LOL!!! I never leave home without my ghijak!!! When I show up to a party with that thing the assclowns with guitars run and hide!!!!
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def
6 points. No deductions. I know we want to use slang words, right? |
this hurts my brain
hi 3 points :D |
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No and yes. |
Aegilops
33 points End of Thread. |
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Since you've reached the end, you should go back to the top and read the rules. |
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-3 points |
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is it not 33 points? |
Sing the alphabet song and determine at what point you recite the letters "a-e-g-i-l-o-p-s" consecutively.
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The letters are in consecutive order according to thier place in the alphabet.
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Fine.
Me=Fail. |
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-2. Better than your last effort. :) |
Since I watch Sesame Street, what about:
ABCDEFGHIJKLMNOPQRSTUVWXYZ ? Big Bird sings a song about it. Pronounced something like: Abkedefkeyjekerminopkwuerstiv if my memory serves. Top song on the page at: http://members.tripod.com/Tiny_dancer/ssbigb.html |
I believe that a closer phonetic approximation would be:
abkudefgujeklmunopkerstoovwiksiz |
hijinks- If i have calculated correctly, thats worth 7 I think.
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Ah yes, thanks. |
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No problem. Once you got the damn song stuck in my head I had to share. :p |
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