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Originally Posted by sooner333
But you're now assuming you WILL get a two. However, if you get a 2, then there are only 51 possibly hands.
I guess the only way I know how to say it is that you start out with zero cards, you get any one of 52 cards in the deck. So now you have your one card (it could be any card in the deck). Then your next card can be any other card in the deck, but since you already have one, it cannot be that. So you have 52 possibilities times 51 possibilities.
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Ok, and i don't wanna belabour (sp?) a point that I admit i have no clue about, but I WILL get 1 of 13 cards right? So once i get that 1 card then I have 51 other possibilities, which means...13 * 51? Arghhh, i'm arguing and I know I have to be wrong, whats the matter with me? Thanks for your replies guys, I do apreciate it, even if i sound like a simpleton.