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sooner333
03-08-2005, 02:47 PM
Why is it that a higher pocket pair against overs has slightly better odds than the lower pocket pair? So why do ten's create a bigger favorite over AJ than two's? It seems to me that the cards you need to catch are equal odds of catching. He needs to catch an ace or a jack to win, seems simple.
dixieflatline
03-08-2005, 02:52 PM
Boards like 99883 kill the pocket twos where pocket tens would still win over AJ.
sooner333
03-08-2005, 03:25 PM
Boards like 99883 kill the pocket twos where pocket tens would still win over AJ.

Thanks, can't believe I didn't think about that.
SirFozzie
03-08-2005, 04:51 PM
So why do ten's create a bigger favorite over AJ than two's

Also cards that catch the AJ Pocket pair (namely J, but also A with J) lead to more of a chance of a straight for the pocket 10's. Small, but it helps
Glengoyne
03-08-2005, 04:55 PM
I knew the answer to this. I learned it the first time my A2 with a flop of A2X , gave me all the advantage I needed over the other guy who was holding A-10. That was until the turn brought another "X", counterfeiting my second pair, and leaving me with a two kicker.