Let's see how smart you are...

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  • LetsGoPitt
    Cr*m*n*lly *nd*rr*t*d
    • Jul 2002
    • 5673

    #31
    Re: Let's see how smart you are...

    Let's see...Bill and Dean are both rendered moot, because with an even number of people, it's impossible to get a majority to approve when that same majority would make more by voting him down (and thus having one less person to split the pot with).

    Earl knows that if Charles' turn comes up, he can buy Dean's vote (since Dean will get nothing if Charles is voted down), so to avoid that happening, he wants to make the most he can off of Andrew.

    Charles has to worry that Bill will buy Dean and Earl's votes if his turn comes up, leaving him with nothing, so he probably wants to get what he can.

    I know there's more to this, but I'm tired....
    “In my lifetime, we've gone from Eisenhower to George W. Bush. We've gone from John F. Kennedy to Al Gore. If this is evolution, I believe that in twelve years, we'll be voting for plants.” - Lewis Black

    Comment

    • dkgojackets
      Banned
      • Mar 2005
      • 13816

      #32
      Re: Let's see how smart you are...

      You're right there. Here's the whole thing explained, working backwards.

      If just E is left, he obviously gets 100 pieces. Therefore, the only proposal D could possibly make is 0 for him and 100 for E. At least he has a chance to survive this way. C knows that D will end up with nothing, so by proposing 99 for himself, 1 for D, and 0 for E, he will get Ds vote and thus a majority. B than knows he can get Ds vote for 2 and Es for 1, and so proposes 97 for himself, 0 for C, 2 for D, and 1 for E. Knowing this will be the result if he gets kicked off, A is able to propose 97 for himself, 0 for B, 1 for C, 0 for D, and 2 for E. C and E agree along with A, and we have a successful proposition.

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      • dkgojackets
        Banned
        • Mar 2005
        • 13816

        #33
        Re: Let's see how smart you are...

        Here's another one I like.

        Using one 1, one 2, and one 3, create an equation that equals 19. You may not use any other numbers. You may not combine digits to make a new number (ie 1 and 2 to make 12). You may use any mathematical operation that you want (including sqrt, which does not count as raising to 1/2), raise to a power (must be an available 1,2, or 3 though), natural logs, whatever. All three numbers must be used.


        Basically, you're looking for a formula that when written out is a combination of mathematical symbols/functions/operations, one 1, one 2, and one 3. No other numbers. It equals 19.

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        • LetsGoPitt
          Cr*m*n*lly *nd*rr*t*d
          • Jul 2002
          • 5673

          #34
          Re: Let's see how smart you are...

          Wow...that's a tough one. I'm stumped!
          “In my lifetime, we've gone from Eisenhower to George W. Bush. We've gone from John F. Kennedy to Al Gore. If this is evolution, I believe that in twelve years, we'll be voting for plants.” - Lewis Black

          Comment

          • johnsatchmo
            Rookie
            • Mar 2005
            • 155

            #35
            Re: Let's see how smart you are...

            What the ****? Is Earl some kind of super pirate? Andrew should have just shot those other pirates and taken the loot.

            Comment

            • dkgojackets
              Banned
              • Mar 2005
              • 13816

              #36
              Re: Let's see how smart you are...

              Originally posted by LetsGoPitt
              Wow...that's a tough one. I'm stumped!

              It is very tough, but exciting once you get the answer.

              Oh yeah, pi counts as a number, just so I dont get cos(pi) + cos(pi) ...

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