No one will post in this thread... it's about a physics question....

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  • FlyingFinn
    MVP
    • Jul 2002
    • 3956

    #16
    Re: No one will post in this thread... it's about a physics question....

    You need to understand coupled oscillations... This site may help:

    http://aix1.uottawa.ca/~jkhoury/oscillations.htm

    Comment

    • bgeno
      MVP
      • Jun 2003
      • 4321

      #17
      Re: No one will post in this thread... it's about a physics question....

      Originally posted by ehh
      Four.
      Ditto.
      Originally posted by DaImmaculateONe
      How many brothers does Sub-zero running around in his clothing? No one can seem to kill the right one.

      Comment

      • 94niners
        Banned
        • Apr 2007
        • 327

        #18
        Re: No one will post in this thread... it's about a physics question....

        Originally posted by FlyingFinn
        You need to understand coupled oscillations... This site may help:

        http://aix1.uottawa.ca/~jkhoury/oscillations.htm
        That site only has a system with ONE spring constant. I know how to solve problems with one k. The one I am working on has THREE k's. k1≠k2≠k3.

        That's why I can't get the eigenvalues.

        I'm getting something like this monstrosity:

        λ = {-(k1 + k3) ± √[ (k1 + k3)^2 - 4(k2 + k3)]}/2

        Or something to that effect. Can't recall exactly. But the point is, how the hell am I supposed to get a numerical value from this?

        In other words, I can't solve for a numerical value for λ because I don't have a spring constant matrix that only has one spring constant. My spring constant matrix is made up of things like (k1 + k3) as entries.

        I thus... am totally lost...




        Originally posted by DocHolliday
        I think you would still have to know that weight of the mass to solve this, but Im not very good at physics
        Nah, all you have to do is keep m1 separate from m2. For each m you should get a w.

        Remember, I am not after a numerical value in terms of force, mass, or k. The only numerical values I am after are of the eigenvalues. Then again, maybe those are not going to be numerical values either...

        Comment

        • Blzer
          Resident film pundit
          • Mar 2004
          • 42515

          #19
          Re: No one will post in this thread... it's about a physics question....

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          • bgeno
            MVP
            • Jun 2003
            • 4321

            #20
            Re: No one will post in this thread... it's about a physics question....

            Originally posted by Blzer
            Originally posted by DaImmaculateONe
            How many brothers does Sub-zero running around in his clothing? No one can seem to kill the right one.

            Comment

            • FlyingFinn
              MVP
              • Jul 2002
              • 3956

              #21
              Re: No one will post in this thread... it's about a physics question....

              How about this:
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